1060: 报时助手
问题描述
给定当前的时间,请用英文的读法将它读出来。 时间用时h和分m表示,在英文的读法中,读一个时间的方法是: 如果m为0,则将时读出来,然后加上“o'clock”,如3:00读作“three o'clock”。 如果m不为0,则将时读出来,然后将分读出来,如5:30读作“five thirty”。 时和分的读法使用的是英文数字的读法,其中0~20读作:
0:zero, 1: one, 2:two, 3:three, 4:four, 5:five,
6:six, 7:seven, 8:eight, 9:nine, 10:ten, 11:eleven,
12:twelve, 13:thirteen, 14:fourteen, 15:fifteen, 16:sixteen,
17:seventeen, 18:eighteen, 19:nineteen, 20:twenty
30读作thirty,40读作forty,50读作fifty。 对于大于20小于60的数字,首先读整十的数,然后再加上个位数。如31首先读30再加1的读法,读作“thirty one”。 按上面的规则21:54读作“twenty one fifty four”,9:07读作“nine seven”,0:15读作“zero fifteen”。
输入格式
输入包含两个非负整数h和m,表示时间的时和分。非零的数字前没有前导0。h小于24,m小于60。
输出格式
输出时间时刻的英文。
样例输入
0 15
样例输出
zero fifteen
import java.util.Scanner;
public class Main {
public static void iTime(int a,int b) {
String []S1 = {"zero","one","two", "three", "four", "five", "six","seven","eight","nine","ten","eleven",
"twelve","thirteen","fourteen","fifteen", "sixteen", "seventeen","eighteen", "nineteen","twenty"};
String []S2 = {"","","twenty","thirty","forty","fifty"};
if (b==0) {
if (a<=20) {
System.out.println(S1[a]+" o'clock");
}else {
char []ch = Integer.toString(a).toCharArray();
int status = Integer.parseInt(ch[1]+"");
System.out.println("twenty "+S1[status]+" o'clock");
}
}else {
if (a<=20) {
System.out.print(S1[a]+" ");
}else {
char []ch = Integer.toString(a).toCharArray();
int status = Integer.parseInt(ch[1]+"");
System.out.print("twenty "+S1[status]+" ");
}
if (b<=20) {
System.out.println(S1[b]);
}else {
char []ch = Integer.toString(b).toCharArray();
int status1 = Integer.parseInt(ch[0]+"");
int status2 = Integer.parseInt(ch[1]+"");
System.out.println(S2[status1]+" "+S1[status2]);
}
}
}
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int a,b;
while(in.hasNext()) {
a = in.nextInt();
b = in.nextInt();
iTime(a,b);
}
}
}